Bash script to play .m4v video and .ul audio together

So you have a lot of .m4v video files and a lot of .ul audio files with the same names. That, for example, might be a collection of  CCTV records, where the name of the file is the date and time of when the record was made. Now you would like to play them.

Create a bash script file in ~/bin, /usr/bin or similar directory. Paste the code inside. Add execution rights. Then run the script with .m4v video  file name as the only argument. The script will figure out name of the audio file on its own and afterwards it will play it all with a bunch of various parameters.

Let’s call it playit:

#!/bin/bash
 videoFile=$1
 audioFile="${videoFile%.*}.ul"
 mplayer -fps 25 -vf denoise3d=0:0:100:0 -cache 16000 -framedrop $videoFile -audiofile $audioFile -audio-demuxer rawaudio -rawaudio format=0x0007:channels=1:rate=8000

Later you can play all video files in the current directory with their accompanying audio files by means of another script, let’s call this one playall:

#!/bin/bash
 for i in *.m4v; do
    playit $i
 done

And another improvement. A script to look into all subdirectories of the current directory and play media found there. Useful if you have your packs of audio &  video files stored in timestamped directories. Let’s call this one playdirs:

#!/bin/bash
rootDir=$(pwd)
for subDir in */; do
cd $subDir
playall
cd $rootDir
done

And then yet another one. Play only files only in a single directory. That will be playdir:

#!/bin/bash
 subDir=$1
 rootDir=$(pwd)
 cd $subDir
 playall
 cd $rootDir